U2.2 · Intramolecular Force and Potential EnergyPractice · 分子内作用力与势能曲线
Lessons covered:U2.2 Intramolecular Force and Potential EnergyU2.5 Lewis DiagramsU2.7 VSEPR and Bond Hybridization
- 1Multiple choice
The figure shows potential-energy curves for , , and ; X, Y, and Z mark the minima of the three curves. Which matches each minimum to its molecule?
ExplanationA higher bond order means a shorter bond (minimum farther left) and a larger bond energy (deeper minimum). N≡N 110 pm, 941 kJ/mol; O=O 121 pm, 495 kJ/mol; F–F 143 pm, 155 kJ/mol. Triple-bonded N₂ is the shortest and deepest, so it is Z; single-bonded F₂ is the longest and shallowest, so it is Y; O₂ is X.
- 2Numeric
The minimum of the potential-energy curve for is at 143 pm and −155 kJ/mol. How much energy is released when 0.250 mol of F atoms all combine to form molecules?
kJExplanationThe depth of the minimum is the bond energy: forming 1 mol of F–F bonds releases 155 kJ. Two F atoms make one , so 0.250 mol of F atoms makes 0.125 mol of , releasing 0.125 × 155 = 19.4 kJ. Multiplying 0.250 × 155 directly double-counts.
- 3Multiple choice
Which ranks the carbon–oxygen bond length in these molecules from shortest to longest?
ExplanationDraw the Lewis diagrams first: has a C≡O triple bond, has two C=O double bonds, and has a C–O single bond. Between the same two atoms, a higher bond order means more shared electrons pulling the nuclei closer, so a shorter bond: < < .
Review: U2.2 Intramolecular Force and Potential EnergyU2.5 Lewis Diagrams
- 4Multiple choice
The average C–C bond energy is 348 kJ/mol, and the C=C bond energy is 614 kJ/mol, less than 2 × 348 = 696 kJ/mol. Which is the best explanation?
ExplanationC=C is one σ bond plus one π bond. A σ bond forms by end-on overlap, which is extensive; a π bond forms by side-by-side overlap of p orbitals, which is weaker, so the double bond is less than twice as strong as a single bond. C=C (134 pm) is actually shorter than C–C (154 pm), and breaking a bond always absorbs energy.
Review: U2.2 Intramolecular Force and Potential EnergyU2.7 VSEPR and Bond Hybridization
- 5Multiple choice
An H atom and a Br atom start far apart and approach each other until their nuclei are 141 pm apart, the minimum of the HBr potential-energy curve. How does the potential energy of the system change?
ExplanationFar apart, the atoms don’t interact, and the potential energy is taken as 0. As they approach, each nucleus attracts the other atom’s electrons; attraction dominates and the energy falls. At 141 pm attraction and repulsion balance, giving the minimum of −366 kJ/mol, the H–Br bond energy. The drop in potential energy is released, so forming a bond releases energy.
- 6Multiple choice
The graph shows the potential energy of two oxygen atoms against the distance between their nuclei (the molecule). From the graph, what are the approximate bond length and bond energy of the O=O bond?
ExplanationThe bond length is the distance at the lowest point of the curve: about 121 pm. The bond energy is the energy needed to climb from that minimum (about −495 kJ/mol) to zero, where the atoms are separated: about 495 kJ/mol, a positive number because breaking a bond absorbs energy. The curve crosses zero near 63 pm, which is just where the potential energy happens to be zero, not the bond length; the flat part on the right means the atoms have separated.
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