U9.4 · Thermodynamic and Kinetic ControlPractice · 热力学控制与动力学控制
Lessons covered:U9.4 Thermodynamic and Kinetic ControlU9.5 Free Energy and Equilibrium (ΔG° = −RT ln K)
- 1Multiple choice
At 25 °C, diamond turning into graphite has ΔG° < 0, yet a diamond ring can be worn for centuries without becoming graphite. Why?
ExplanationThermodynamics says graphite is more stable (ΔG° < 0); kinetics says the conversion is extremely slow, because rearranging the whole covalent network has an enormous activation energy. That is kinetic control. Diamonds last because the change is slow, not because they are more stable.
- 2Multiple choice
A catalyst is added to a reaction that is thermodynamically favorable but slow. Which statement is correct?
ExplanationA catalyst provides a pathway with a lower activation energy, speeding up the forward and reverse reactions equally so equilibrium is reached sooner. ΔG° depends only on the initial and final states, and K is set by ΔG°, so neither changes.
- 3Multiple choice
Ammonia and oxygen can undergo two reactions: ① 4NH₃(g) + 3O₂(g) → 2N₂(g) + 6H₂O(g), ΔG° = −1306 kJ; ② 4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O(g), ΔG° = −955 kJ. Industrially, on a platinum–rhodium catalyst, ammonia is oxidized mainly to NO (reaction ②). Which is the best explanation?
ExplanationBoth reactions are thermodynamically favorable, and making N₂ (①) is even more so (−1306 kJ versus −955 kJ). NO forms because the catalyst greatly speeds up ②, so in the brief contact time NO is the main product. A catalyst doesn’t change any reaction’s ΔG°.
- 4Multiple choice
A reaction has ΔG° = +35 kJ/mol at 25 °C. Which statement is correct?
ExplanationΔG° > 0 corresponds to K < 1 (here about 10⁻⁶): little product at equilibrium, but not none. A catalyst changes only the rate, not ΔG° or K. And ΔG° says nothing about speed: a reaction with a small K can still reach equilibrium quickly.
Review: U9.4 Thermodynamic and Kinetic ControlU9.5 Free Energy and Equilibrium (ΔG° = −RT ln K)
- 5Multiple choice
An exothermic reaction is thermodynamically favorable but kinetically controlled (slow at room temperature). What does raising the temperature do?
ExplanationRaising the temperature gives more molecules enough energy to clear the activation barrier, so any reaction speeds up. But for an exothermic reaction, heating shifts the equilibrium backward and lowers K (and ΔG° = ΔH° − TΔS° changes with temperature too). Industry often has to balance speed against yield.
Your missed questions were saved automatically to your mistake notebook · 0
Your best score counts only full runs through the set, not retries of missed questions.