U5.6 · Reaction Energy ProfilePractice · 反应能量图
Lessons covered:U5.5 Collision ModelU5.6 Reaction Energy Profile
- 1Numeric
The energy profile of a one-step reaction is shown (values in kJ/mol). What is the activation energy of the forward reaction?
kJ/molExplanationThe activation energy is the gap from the reactants up to the transition state (the peak): 110 − 30 = 80 kJ/mol. Don’t measure from zero, and don’t subtract the products (that gives the reverse activation energy, 60 kJ/mol).
Review: U5.6 Reaction Energy Profile
- 2Multiple choice
Continuing: what is ΔH for this reaction?
ExplanationΔH = energy of products − energy of reactants = 50 − 30 = +20 kJ/mol. The products lie above the reactants, so the reaction is endothermic. ΔH has nothing to do with the activation energy.
Review: U5.6 Reaction Energy Profile
- 3Numeric
A one-step reaction has a forward activation energy of 65 kJ/mol and ΔH = +25 kJ/mol. What is the activation energy of the reverse reaction?
kJ/molExplanationSketch it: the reactants are 65 below the transition state, and the products are 25 above the reactants, so the products are only 65 − 25 = 40 kJ/mol below the peak. For an endothermic reaction, the reverse activation energy is the smaller one.
Review: U5.6 Reaction Energy Profile
- 4Multiple choice
These four one-step energy profiles are drawn to the same scale. At the same temperature (other factors similar), which reaction is exothermic and fastest?
ExplanationExothermic: products below reactants (A and C). Fastest: the smallest activation energy, the height from reactants to the peak. C has the lowest peak, so it is the exothermic and fastest one. B also has a small barrier but its products are higher (endothermic), and A and D have tall barriers.
Review: U5.6 Reaction Energy Profile
- 5Multiple choice
When the temperature rises from 25 °C to 35 °C, the rate constant of reaction 1 triples and that of reaction 2 doubles. How do their activation energies compare?
ExplanationThe higher the energy requirement (the larger Ea), the rarer the qualifying collisions, so heating multiplies them by a bigger factor and k is more sensitive to temperature. From the Arrhenius equation, a 3-fold rise in k over 10 °C corresponds to ≈ 85 kJ/mol and a 2-fold rise to about 53 kJ/mol.
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