Physical and Chemical Changes物理变化与化学变化

Big Idea · Transformations (TRA)AP Science Practice 6 · ArgumentationAP link · Unit 4~40 min

Learning goals

  • Explain whether a process is a physical or a chemical change by whether chemical bonds or intermolecular forces are broken and formed
  • Compare the energies involved in changes of state and in chemical reactions, and explain that chemical bonds are generally much stronger than intermolecular forces
  • Explain why processes such as dissolving an ionic compound are hard to classify, and describe them by the interactions broken and formed

Before you start

  • Physical and chemical changes (1.2.3)
  • Intermolecular forces (U3.1)
  • Enthalpy change and thermochemical equations (2.10.5)

Look at what gets broken

U4.1 classified changes by whether a new substance forms. AP topic 4.4 goes one level deeper and asks which interactions are broken and formed:

  • Chemical change: chemical bonds化学键 (covalent, ionic, or metallic) are broken or formed, and atoms rearrange.
  • Physical change: only the intermolecular forces分子间作用力 between particles change (dispersion forces, dipole–dipole forces, hydrogen bonds); each molecule stays intact.

So when water boils, the hydrogen bonds between water molecules are broken, while the O–H bonds inside every H₂O molecule are untouched; only when water decomposes into H₂ and O₂ are O–H covalent bonds broken.

How much energy

Chemical bonds are generally much stronger than intermolecular forces. Compare the energies per mole:

ProcessInteractions brokenEnergy (kJ/mol)
Ice meltingSome hydrogen bonds6.01
Water boilingHydrogen bonds40.7
H₂O decomposing into H₂ and ½O₂2 O–H covalent bondsabout 926
H₂ + Cl₂ → 2HClThe H–H and Cl–Cl bondsabout 678

The enthalpies of fusion and vaporization come from the CRC Handbook; the bond energies are average bond enthalpies (Brown et al., Chemistry: The Central Science). Physical changes typically involve a few to a few tens of kJ/mol, while the bonds broken in a chemical reaction typically take hundreds of kJ/mol.

A gray area: dissolving an ionic compound

When NaCl dissolves in water, the ionic bonds between Na⁺ and Cl⁻ are broken (the lattice energy is about 786 kJ/mol), while ion–dipole interactions form between the ions and water molecules, releasing almost as much energy; the net enthalpy of solution is only +3.88 kJ/mol.

  • By whether a new substance forms: none does, and evaporating the water gives NaCl back, so it looks physical.
  • By whether chemical bonds are broken: ionic bonds are, so it looks chemical.

AP accepts that such processes can be classified either way. Rather than asking only which kind of change it is, the exam expects you to describe the interactions broken and formed.

Some salts react further after they dissolve. When sodium acetate dissolves, the CH₃COO⁻ ions take H⁺ from some water molecules, acting as a Brønsted–Lowry base (U4.8) to form a little CH₃COOH and OH⁻, so the solution is basic:

CHX3COOX−(aq)+HX2O(l)⇌CHX3COOH(aq)+OHX−(aq)\ce{CH3COO-(aq) + H2O(l) <=> CH3COOH(aq) + OH-(aq)}

That step breaks O–H bonds and forms new ones, so it is a chemical change.

Compare six processes, the interactions broken in each, and the energy needed:

Try it: are intermolecular forces or chemical bonds being broken?

HX2O(s)→HX2O(l)\ce{H2O(s) -> H2O(l)}

Before
After

Physical change

  • Broken: some of the hydrogen bonds between water molecules (needs about 6.01 kJ/mol)

The water molecules themselves (their O–H covalent bonds) are unchanged; only their arrangement changes: a physical change.

Energy needed to break these interactions (kJ/mol, log scale)

11010010³10⁴Ice melts6.01Water boils40.7NaCl dissolves786Water splits926H₂ + Cl₂678CH₄ burns2642kJ/mol
HONaClCPhysical changeChemical changeClassified either way

Example 1: Boiling versus electrolysis

Boiling water and electrolyzing water both produce bubbles. Compare the two processes in terms of the interactions broken and the energy involved.

Step-by-step solution
  1. Identify: what boiling breaks. In boiling the H₂O molecules are unchanged, and the bubbles are water vapor; what’s overcome is the hydrogen bonding and other intermolecular forces between molecules. The energy needed is the enthalpy of vaporization, about 40.7 kJ/mol.

  2. Identify: what electrolysis breaks. In electrolysis the O–H covalent bonds inside the H₂O molecules break and the atoms recombine into H₂ and O₂, so the bubbles are new substances. Each H₂O molecule has 2 O–H bonds (bond energy about 463 kJ/mol), so per mole of H₂O (in kJ):

    2×463=9262 \times 463 = 926
  3. Compare the energies.

    92640.7≈23\frac{926}{40.7} \approx 23

    Breaking the O–H bonds takes over 20 times the enthalpy of vaporization.

  4. Connect to the type of change. Boiling overcomes only intermolecular forces: a physical change. Electrolysis breaks covalent bonds and forms new substances: a chemical change. Covalent bonds are much stronger than intermolecular forces, which is why the energies differ so much.

Example 2: Two changes of iodine

When iodine is heated, the violet-black solid turns into a violet vapor; at very high temperatures, I₂ molecules in the vapor break apart into iodine atoms. Explain how the interactions broken differ in the two processes.

Step-by-step solution
  1. Identify: what sublimation breaks. I₂(s) → I₂(g): there are I₂ molecules before and after; what’s overcome is the dispersion forces between I₂ molecules, and the I–I covalent bond stays intact: a physical change.
  2. Identify: what dissociation breaks. I₂(g) → 2I(g): the I–I covalent bond (151 kJ/mol) breaks, forming new particles, iodine atoms: a chemical change.
  3. Compare the strengths. The I–I covalent bond is much stronger than the dispersion forces between I₂ molecules, so breaking it takes more energy.
  4. Connect to temperature. More energy means a higher temperature: iodine sublimes with gentle heating, but I₂ molecules break apart noticeably only at very high temperatures.
  5. The method. For any change of one substance, ask: “Is what’s broken the attraction between molecules, or a bond inside them?” The first is a physical change; the second is a chemical change.
Practice: what does this process mainly break?
  1. Ethanol boiling
  2. Ethanol burning
  3. Candle wax melting
  4. Dry ice subliming
  5. Electrolyzing molten NaCl into Na and Cl₂
  6. Sugar dissolving in water
  7. Hydrogen peroxide decomposing
  8. Steam condensing into water
  9. I₂ molecules splitting into iodine atoms
  10. Iodine subliming
  11. Compressing water vapor at constant temperature until droplets form

Common mistakes

Mistake 1: “When water boils, its molecules break into hydrogen and oxygen, so the bubbles are H₂ and O₂.” Boiling overcomes only the hydrogen bonds between water molecules; the bubbles are water vapor. Breaking O–H bonds takes far more energy.

Mistake 2: “Physical changes involve no energy change.” Melting, boiling, and dissolving all absorb or release energy, usually less than chemical reactions do. An energy change alone can’t tell the two kinds of change apart.

Mistake 3: “Intermolecular forces are just weak chemical bonds.” Chemical bonds are inside molecules, holding atoms together; intermolecular forces act between molecules. Breaking chemical bonds gives new particles; overcoming intermolecular forces leaves the original molecules.

Quick check

Which process requires overcoming only intermolecular forces?

The enthalpy of vaporization of water is 40.7 kJ/mol, and the average O–H bond enthalpy is 463 kJ/mol. Which statement is best?

Some books call dissolving NaCl in water a physical change and others a chemical change. Which explanation is best?

What is overcome when iodine sublimes?

Which pair of energies is most likely to be for a physical change and a chemical change, in that order?

A student says, “Ice absorbs heat when it melts, so melting is a chemical change.” Which rebuttal is best?

Hydrogen peroxide decomposing into water and oxygen is a chemical change. Which reason is best?

A vapor is compressed at constant temperature. At first the pressure rises as the volume decreases; once droplets appear, the volume keeps decreasing but the pressure stays constant. What is happening during the constant-pressure stage?

AP-style free response

AP-style free response

The table gives the energies of some interactions:

InteractionEnergy (kJ/mol)
Enthalpy of vaporization of H₂O40.7
Average O–H bond enthalpy463
Lattice energy of NaCl786
Enthalpy of solution of NaCl+3.88

(a) Which kind of interaction is overcome when water boils? Use the data to show that water molecules don’t decompose when water boils.

(b) Calculate the energy needed to break all the O–H bonds in 1 mol of gaseous water molecules, and identify what kind of change this is.

(c) Breaking the ionic bonds when NaCl dissolves takes about 786 kJ/mol, yet the enthalpy of solution is only +3.88 kJ/mol. Explain why the two values differ so much.

(d) Use your answer to (c) to explain why “Is dissolving NaCl in water a physical or a chemical change?” has no single answer.

Model answer and scoring

(a) The hydrogen bonds between water molecules (intermolecular forces) are overcome. The enthalpy of vaporization, 40.7 kJ/mol, is far less than the O–H bond enthalpy of 463 kJ/mol, so boiling doesn’t supply enough energy to break covalent bonds, and the water molecules stay intact.

(b) Each H₂O molecule has 2 O–H bonds: 2 × 463 = 926 kJ. Breaking covalent bonds lets the atoms recombine (for example into H₂ and O₂), a chemical change.

(c) Breaking the ionic bonds takes about 786 kJ/mol, but as the ions enter the water, ion–dipole interactions form and release almost as much energy (about 782 kJ/mol). The two largely cancel, so the net enthalpy of solution is small.

(d) Dissolving breaks ionic bonds, which makes it look chemical; but no new substance forms, and evaporating the solution gives NaCl back, which makes it look physical. So the process should be described by the interactions broken and formed rather than given a single label.

Scoring: (a) hydrogen bonds, comparing 40.7 with 463; (b) 926 kJ, a chemical change; (c) ion–dipole interactions form, releasing energy that nearly cancels the lattice energy; (d) both points of view explained.

Summary

  • Chemical changes break or form chemical bonds; physical changes only change intermolecular forces, and the molecules stay intact.
  • Chemical bonds are generally much stronger than intermolecular forces: changes of state take a few to a few tens of kJ/mol, breaking bonds hundreds.
  • Dissolving an ionic compound breaks ionic bonds but forms no new substance, so it can be classified either way; describe the interactions broken and formed.
  • An energy change on its own doesn’t distinguish physical from chemical changes.

AP tip: To explain why boiling doesn’t decompose water molecules, state both that intermolecular forces are overcome (name which kind) and that they are much weaker than covalent bonds, ideally with numbers.

Practice this chapter: Unit 4 · Chemical Reactions · 12 questionsPractice this topic: U4.4 · Physical and Chemical Changes · 5 questions

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