Photoelectron Spectroscopy (PES)光电子能谱(PES)

Big Idea · Structure and Properties (SAP)AP Science Practice 4 · Model AnalysisAP link · Unit 1~45 min

Learning goals

  • Describe how photoelectron spectroscopy works: photons of known energy eject electrons, and binding energy = photon energy − kinetic energy of the electron
  • Read a PES spectrum, where peak position (binding energy, higher on the left) identifies the sublevel and peak height is proportional to the number of electrons, and use it to write a configuration or identify an element
  • Explain peak positions with Coulomb's law: inner sublevels lie to the left within an atom, and for the same sublevel in different species, more protons means farther left

Before you start

  • Light and spectra (c = λν, E = hν) (2.2.2)
  • Ionization energy (2.3.4)
  • Atomic structure and electron configuration (U1.5)

Weighing the electrons in every sublevel

First ionization energy (lesson 2.3.4) only tells us the energy needed to remove the outermost electron. What about the inner ones? In U1.5, Coulomb’s law predicted that 1s electrons are the hardest to remove and valence electrons the easiest. Photoelectron spectroscopy (PES) measures the energy of the electrons in every sublevel directly, turning that prediction into data and giving the most direct evidence for electron configurations.

How PES works

Shine high-energy photons of known energy (ultraviolet light or X-rays) on gaseous atoms, and the photons knock electrons out: the photoelectric effect from lesson 2.2.2. The ejected electrons are called photoelectrons, and the instrument measures their kinetic energy. Part of the photon’s energy overcomes the attraction holding the electron, and the rest becomes the electron’s kinetic energy:

Ebinding=hν−EkE_{\text{binding}} = h\nu - E_{\text{k}}

The energy needed to remove an electron from a given sublevel is that sublevel’s binding energy结合能. PES usually reports it in MJ/mol (1 MJ/mol = 1000 kJ/mol); per electron it’s often given in electron volts, and 1 eV corresponds to 0.096485 MJ/mol.

Electrons from every sublevel can be ejected, and the number ejected is proportional to the number of electrons in the sublevel. A plot of “how many electrons” against binding energy is a photoelectron spectrum光电子能谱.

Reading a PES spectrum

  • The horizontal axis is binding energy, increasing to the LEFT on AP spectra. The leftmost peak is 1s, and the rightmost is the outermost electrons.
  • Each peak is one sublevel. The number of peaks is the number of occupied sublevels.
  • Peak height is proportional to the number of electrons. An s peak is at most 2 high and a p peak at most 6, so comparing heights tells you how many electrons each sublevel holds.
  • The rightmost peak’s binding energy is the first ionization energy.

Measured data for neon and argon (MJ/mol):

Sublevel1s2s2p3s3p
Ne84.04.682.09——
Ar30931.524.02.831.52
Peak height (electrons)22626

(LBNL X-ray Data Booklet, Table 1-1, converted from eV; the two spin–orbit components of 2p and 3p are combined into one peak, weighted by their electrons.) Reading left to right gives Ne as 1s²2s²2p⁶ and Ar as 1s²2s²2p⁶3s²3p⁶. Neon’s rightmost peak, 2.09 MJ/mol, is almost exactly its first ionization energy of 2081 kJ/mol, and argon’s 1.52 matches its 1521 kJ/mol.

Explaining peak positions with Coulomb’s law

Within one atom: 1s electrons are closest to the nucleus and feel nearly its full charge, so they have the largest binding energy. Electrons farther out are farther away and more shielded, so their binding energies are smaller. Within one shell, 2s lies to the left of 2p: 2p electrons are partly shielded by the 2s electrons and are a little farther out on average. So from left to right the order is always 1s, 2s, 2p, 3s, 3p, 4s.

The same sublevel in different species: when the electrons are in the same shell at about the same distance, more protons mean stronger attraction and a peak farther left. Measured 1s binding energies (MJ/mol):

NOFNeArKr
Protons789101836
1s binding energy39.552.467.284.03091382

(The N, O, and F values are for the gaseous molecules NX2\ce{N2}, OX2\ce{O2}, and FX2\ce{F2}; the rest are free atoms; same source.) Isoelectronic species work the same way: CaX2+\ce{Ca^2+} and Ar both have 18 electrons, so their spectra have the same number of peaks with the same heights, but calcium has 20 protons, so every peak of CaX2+\ce{Ca^2+} lies to the left of argon’s.

AP accepts only two kinds of reasons: more protons (greater nuclear charge), or an electron in a shell farther from the nucleus. None of these earn credit: “a half-filled p sublevel”, “higher electronegativity”, “a heavier nucleus”, “the electron takes longer to remove”, or anything about isotopes (PES measures sublevels and can’t see isotopes; that’s the mass spectrometry of U1.2).

About the spectra on this page

Every peak of He, Ne, Ar, and Kr is a measured value. Precise free-atom values for the inner peaks of other elements come from a paywalled compilation that you couldn’t check, so this page draws them as schematics. Peak heights still equal electron counts, and the inner peaks show only their left-to-right order (for the same sublevel, more protons means farther left), not their true positions. The rightmost peak is drawn on a real scale: it is the first ionization energy. AP questions always give you the spectrum, and what you need to read is exactly the number of peaks, their heights, and their order.

Look at the complete spectra of Ne, Ar, and Kr first, then the schematics of Na and O. Then count peak heights in “Identify the element”, and overlay two elements in “Compare two”:

Try it: read photoelectron spectra

Data: He, Ne, Ar, Kr, and the 1s values in N₂, O₂, F₂ from the LBNL X-ray Data Booklet, Table 1-1 (1 eV = 0.096485 MJ/mol; spin–orbit pairs combined, weighted by electrons); rightmost peaks are first ionization energies (CRC/NIST).

Example 1: Identifying an element from its spectrum

The PES of an element has 5 peaks with relative heights 2 : 2 : 6 : 2 : 1 from left to right, and the rightmost peak has a binding energy of 0.578 MJ/mol. What is the element?

Step-by-step solution
  1. Assign each peak to a sublevel. A PES runs from high binding energy on the left to low on the right, so the peaks go from the sublevel nearest the nucleus outward: 1s, 2s, 2p, 3s, 3p.

  2. Read electron counts from peak heights. Relative height is proportional to the number of electrons in that sublevel:

    • 1s: 2, 2s: 2, 2p: 6
    • 3s: 2, 3p: 1

    The configuration is 1s²2s²2p⁶3s²3p¹.

  3. Count the electrons. A neutral atom has as many electrons as its atomic number:

    2+2+6+2+1=132 + 2 + 6 + 2 + 1 = 13

    This is element 13, aluminum (Al)\boxed{\text{aluminum (Al)}}.

  4. Check with data. The rightmost peak is the single 3p electron, the easiest to remove, so its binding energy is the first ionization energy:

    0.578 MJ/mol=578 kJ/mol0.578\ \text{MJ/mol} = 578\ \text{kJ/mol}

    That is aluminum’s first ionization energy. It matches.

Example 2: How do the spectra of Ne and Na differ?

Compare the PES of Ne and Na: how do the number, heights, and positions of the peaks differ, and why?

Step-by-step solution
  1. Identify: write the configurations.

    • Ne: 1s²2s²2p⁶ (10 electrons, 10 protons)
    • Na: 1s²2s²2p⁶3s¹ (11 electrons, 11 protons)
  2. Compare the number and heights of peaks. Na has one extra peak, 3s, with height 1 (one electron); the first three peaks have heights 2 : 2 : 6 in both.

  3. Where the extra 3s peak sits. The 3s electron is in n = 3, far from the nucleus and shielded by 10 core electrons, so it is weakly attracted and its binding energy is very small (0.496 MJ/mol, sodium’s first ionization energy). It is the rightmost peak.

  4. Compare the positions of the first three peaks. The 1s, 2s, and 2p shells are the same in both, but Na has 11 protons, one more than Ne, so those electrons are attracted more strongly. Each Na peak lies to the left (higher binding energy) of the matching Ne peak.

  5. Connect to the spectra. In summary:

    • Number: Na has one more peak (3s).
    • Heights: the first three match; the 3s peak has height 1.
    • Positions: Na’s 1s, 2s, and 2p peaks shift left.
Practice: which one has this peak farther left (higher binding energy)?
  1. 1s peak: C or N
  2. 1s peak: Ar or CaX2+\ce{Ca^2+}
  3. 2p peak: Na or Mg
  4. Rightmost peak: N or O
  5. Rightmost peak: Na or K
  6. 1s peak: a ³⁵Cl atom or a ³⁷Cl atom
  7. 2s peak: Ne or Ar
  8. 1s peak: O or F
  9. Rightmost peak: Be or B

Common mistakes

Mistake 1: “A taller peak means a higher binding energy.” A peak’s height is the number of electrons; its position is the binding energy. Neon’s 2p peak is the tallest (6 electrons), yet it’s the rightmost, with the smallest binding energy.

Mistake 2: Mixing up PES and mass spectrometry. In a mass spectrum (U1.2) the peaks are isotopes and the horizontal axis is mass-to-charge ratio; in PES the peaks are sublevels and the horizontal axis is binding energy. PES can’t distinguish isotopes and has nothing to do with oxidation states.

Mistake 3: Explaining peak positions with “half-filled”, electronegativity, or a heavier nucleus. Oxygen’s 1s peak lies to the left of nitrogen’s for one reason: oxygen has more protons, which attract its 1s electrons more strongly. Those other explanations earn no credit.

Quick check

The PES of an element has 4 peaks with relative heights 2 : 2 : 6 : 1 from left to right. The element is

The 1s peak of an O atom lies to the left of (higher binding energy than) the 1s peak of an N atom. Which is the best explanation?

In the PES of argon, the rightmost peak corresponds to which sublevel?

The PES of CaX2+\ce{Ca^2+} has the same number of peaks with the same heights as the PES of Ar, but every peak of CaX2+\ce{Ca^2+} lies farther left. Why?

Which of the following can NOT be determined from the PES of an element?

AP-style free response

AP-style free response

Photoelectron spectroscopy data for Ne and Ar are given below (binding energies in MJ/mol). Ne: 84.0, 4.68, 2.09. Ar: 309, 31.5, 24.0, 2.83, 1.52.

(a) Identify the sublevel and relative peak height for each peak in the spectrum of Ar.

(b) Explain why the 1s binding energy of Ar is much greater than that of Ne.

(c) Ar has more protons than Ne, yet the rightmost peak of Ar (1.52) has a lower binding energy than the rightmost peak of Ne (2.09). Explain.

(d) Describe how the PES of Na differs from the PES of Ne.

Model answer and scoring

(a) From left to right: 309 is 1s, height 2; 31.5 is 2s, height 2; 24.0 is 2p, height 6; 2.83 is 3s, height 2; 1.52 is 3p, height 6.

(b) Both 1s sublevels are in n = 1, very close to the nucleus, but argon has 18 protons to neon’s 10. Argon’s nucleus exerts a much stronger Coulombic attraction on its 1s electrons, so removing one takes much more energy.

(c) Argon’s outermost electrons are in 3p (n = 3); neon’s are in 2p (n = 2). Argon’s 3p electrons are farther from the nucleus and shielded by 10 core electrons, so the effective nuclear charge they feel is not much larger than neon’s 2p electrons feel. The greater distance means weaker attraction and a lower binding energy.

(d) Na (1s²2s²2p⁶3s¹) has one extra peak: at the far right, with height 1 and a very small binding energy (0.496 MJ/mol, sodium’s first ionization energy). Its 1s, 2s, and 2p peaks have the same heights as neon’s, but because sodium has one more proton, each of those three peaks lies to the left of neon’s (higher binding energy).

Scoring: (a) correct sublevels and heights; (b) both “both in n = 1” and “18 protons against 10”; (c) “n = 3, farther away” plus shielding, while “argon is bigger” alone is not enough; (d) both “an extra peak of height 1 at the far right” and “the other peaks shift left”.

Summary

  • PES ejects electrons with photons of known energy: binding energy = photon energy − photoelectron kinetic energy, usually in MJ/mol.
  • Binding energy increases to the left; each peak is a sublevel, and peak height is the number of electrons. Read the configuration from left to right; the heights add up to the total number of electrons.
  • The rightmost peak is the outermost electrons, and its binding energy equals the first ionization energy.
  • Within an atom, inner electrons are closer and less shielded, so their peaks are to the left; for the same sublevel in different species, more protons means farther left. Only nuclear charge and distance count as reasons.

AP tip: The most common PES questions ask you to write a configuration or identify an element from a spectrum, compare the position of the same peak in two species and explain it, point out which peak is the valence electrons or the first ionization energy, or say which peak is tallest. To explain a position, use only “number of protons (nuclear charge)” and “which shell the electron is in (distance, shielding)”. The photoelectric effect itself returns in U3.12.

Practice this chapter: Unit 1 · Atomic Structure and Properties · 12 questionsPractice this topic: U1.6 · Photoelectron Spectroscopy (PES) · 5 questions

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