Introduction to Equilibrium平衡入门

Big Idea · Transformations (TRA)AP Science Practice 6 · ArgumentationAP link · Unit 7~40 min

Learning goals

  • Explain that when a reversible process reaches equilibrium in a closed system, the forward and reverse rates are equal and the concentrations (or partial pressures) stop changing
  • Distinguish “concentrations are constant” from “concentrations are equal,” and explain why equilibrium is dynamic
  • Use concentration–time graphs, rate–time graphs, and experimental data to decide when a system has reached equilibrium

Before you start

  • Reversible reactions and dynamic equilibrium (2.11.3)
  • Reaction rates (U5.1)
  • Solids, liquids, and gases (U3.3)

Forward and reverse at the same time

Many processes can run both ways: a liquid evaporates and its vapor condenses; a solid dissolves and its ions crystallize again; N₂O₄ breaks apart into NO₂ and NO₂ joins back into N₂O₄. In a closed system both directions happen at once. At first the forward process is faster; as reactants are used up and products build up, the forward process slows and the reverse speeds up, until the two rates are equal. The system is then at chemical equilibrium化学平衡 (or physical equilibrium, for a physical process).

At equilibrium:

  • the forward and reverse rates are equal;
  • the concentrations (or partial pressures) stay constant, but are generally not equal to each other;
  • neither process has stopped, so the equilibrium is dynamic;
  • the system must be closed and at constant temperature.

Physical equilibrium: evaporation in a closed container

When a liquid evaporates in a closed container, more and more gas molecules build up, and more of them hit the surface and are captured again. Once condensation catches up with evaporation, the number of gas molecules stops changing; the pressure of the gas is then the vapor pressure of the liquid at that temperature (U3.3). Compare closed and open containers, two temperatures, and two amounts of liquid:

Try it: evaporation and condensation in a container

The rates and numbers are schematic: the evaporation rate at 45 °C is taken as 3 times that at 25 °C.

Chemical equilibrium: reachable from either side

N₂O₄(g) ⇌ 2NO₂(g) can start from N₂O₄ alone or from NO₂ alone. Watch how the concentrations and rates change with time:

Try it: how N₂O₄ ⇌ 2NO₂ reaches equilibrium
Start with
Color of the gas (NO₂ is red-brown)

Whichever side it starts from, at the same temperature and with equivalent amounts of atoms, it reaches the same equilibrium composition.

Example 1: Reading experimental data

At a certain temperature, 0.500 mol of A(g) is placed in a closed 1.00 L container, where A(g) ⇌ 2B(g). The concentration of A is measured:

Time (s)01020304050
[A] (M)0.5000.3800.3200.3000.3000.300

When is equilibrium reached, and what is [B] at equilibrium?

Step-by-step solution
  1. Find the plateau. [A] is 0.300 M at 30 s, 40 s and 50 s and no longer changes, so equilibrium has been reached by 30 s.

  2. Organize the concentrations in a table. At the start [A] = 0.500 mol ÷ 1.00 L = 0.500 M, with no B. If A decreases by x, B increases by 2x, following the coefficients (concentrations in M):

    A2B
    Start0.5000
    Change−x+2x
    Equilibrium0.3002x
  3. Find x from A.

    0.500−x=0.300x=0.200\begin{aligned} 0.500 - x &= 0.300 \\ x &= 0.200 \end{aligned}
  4. Find [B]. Each mole of A that reacts forms 2 mol of B:

    [B]=2x=2×0.200=0.400 M[\ce{B}] = 2x = 2 \times 0.200 = \boxed{0.400\ \text{M}}
  5. Note. At equilibrium [A] = 0.300 M and [B] = 0.400 M, which are not equal. The sign of equilibrium is that the concentrations stop changing, not that they become equal.

Example 2: How can you show equilibrium is dynamic?

A saturated NaCl solution at 25 °C has NaCl crystals at the bottom. A little solid NaCl containing radioactive ²⁴Na is added, stirred in, and left to stand. Later, radioactivity is detected in the solution, while the total [Na⁺] in the solution has not changed. What does this show?

Step-by-step solution
  1. Solution concentration. The solution stays saturated, so the total [Na⁺] is unchanged; nothing seems to happen.
  2. Where the radioactivity went. The ²⁴Na started only in the solid but ended up in the solution, so solid is still dissolving.
  3. Why the concentration is constant. At the same time an equal amount of Na⁺ and Cl⁻ crystallizes back onto the solid; dissolving and crystallizing happen at the same rate.
  4. Conclusion. The solubility equilibrium is dynamic: both processes continue at equal rates.
Practice: a reversible reaction in a closed container has reached equilibrium. Must each statement be true?
  1. The forward rate equals the reverse rate
  2. The reactant concentrations equal the product concentrations
  3. No concentration changes with time any more
  4. Both the forward and reverse reactions have stopped
  5. The color of a colored substance no longer changes
  6. All of the reactants have turned into products
  7. At the same temperature, starting from the products leads to the same equilibrium
  8. The ratio of the amounts of reactants and products equals the ratio of coefficients

Common mistakes

Mistake 1: “At equilibrium, the reactant and product concentrations are equal.” At equilibrium the concentrations stop changing, but they are generally not equal. Constant ≠ equal.

Mistake 2: “Once equilibrium is reached, the reaction stops.” Both the forward and reverse reactions continue at equal rates, so there is no visible change.

Mistake 3: “A liquid in an open container reaches evaporation equilibrium too.” In an open container, gas molecules keep escaping and condensation never catches up with evaporation. Equilibrium can only be established in a closed system.

Quick check

In a closed container, a reversible reaction starts with only reactants. Before equilibrium is reached, which statement is correct?

A sealed flask contains a little liquid ethanol at a constant 20 °C, and the pressure of ethanol vapor in the flask is no longer changing. Which statement is correct?

Which observation shows that a reversible reaction in solution has reached equilibrium?

Two identical closed containers are at the same temperature. Container 1 starts with 0.20 mol of N₂O₄ and container 2 with 0.40 mol of NO₂. After a long time, the gases in the two containers:

For X ⇌ Y in a closed container, a concentration–time graph is drawn. What marks the point at which equilibrium is reached?

Which of these systems cannot reach equilibrium?

AP-style free response

AP-style free response

With an acid catalyst, acetic acid and ethanol react to form ethyl acetate and water: CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂O. A student mixes 1.00 mol of acetic acid with 1.00 mol of ethanol at constant temperature and measures the amount of ethyl acetate (schematic data):

Time (h)012468
n(ethyl acetate) (mol)00.300.500.620.670.67

(a) By what time has the system reached equilibrium? Justify your answer.

(b) How many moles of acetic acid, ethanol, ethyl acetate, and water are present at equilibrium?

(c) Compare the forward and reverse rates at 6 h.

(d) After 6 h the amount of ethyl acetate stops increasing, yet the reaction has not stopped. Explain this statement.

(e) Another student starts from 1.00 mol of ethyl acetate and 1.00 mol of water under the same conditions. Predict the amount of ethyl acetate at equilibrium, and justify your prediction.

Model answer and scoring

(a) By 6 h. The amounts at 6 h and 8 h are the same, so it is no longer changing.

(b) Ethyl acetate 0.67 mol and water 0.67 mol; acetic acid and ethanol 1.00 − 0.67 = 0.33 mol each.

(c) Equal. The system is at equilibrium, so the forward and reverse rates are equal.

(d) Acetic acid and ethanol are still forming ethyl acetate, while ethyl acetate is hydrolyzed at the same rate, so the net change is zero.

(e) About 0.67 mol. Both starting mixtures contain the same atoms, and at the same temperature both directions reach the same equilibrium composition.

Scoring: (a) amount no longer changing; (b) amounts from the coefficients; (c) equal rates; (d) dynamic equilibrium; (e) the same equilibrium from either side.

Summary

  • When a reversible process reaches equilibrium in a closed system, the forward and reverse rates are equal and the concentrations (partial pressures) stop changing.
  • At equilibrium concentrations are constant but generally not equal; the equilibrium is dynamic, with both processes still occurring.
  • Physical processes (evaporation, dissolving) and chemical reactions can both reach equilibrium, and the same equilibrium can be reached from the reactant side or the product side.
  • Signs of equilibrium: concentration, pressure, color, and so on no longer change.

AP tip: When explaining equilibrium, state both points: “the forward and reverse rates are equal” and “the concentrations remain constant (but are not necessarily equal).” On a graph, look for where the curves level off; don’t mistake the point where curves cross for equilibrium.

Practice this chapter: Unit 7 · Equilibrium · 12 questionsPractice this topic: U7.1 · Introduction to Equilibrium · 6 questions

Found a mistake in this lesson, something unclear, or have a suggestion?

Feedback / Report a problem

Type

We only receive what you write, the page you’re on and any contact you choose to leave. No names or other personal data (to stop spam we keep a one-way hash of your IP, never the IP itself).